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ladybug6
ladybug6 ladybug6
  • 24-09-2015
  • Mathematics
Answered

HELP HOW DO I SOLVE THE FOLLOWING? PLEASE HELP

HELP HOW DO I SOLVE THE FOLLOWING? PLEASE HELP class=

Verified Answer :

Panoyin
Panoyin Panoyin
  • 24-09-2015

\(f(x) = \sqrt[3]{2x - 1} \\f(14) = \sqrt[3]{2(14) - 1} \\f(14) = \sqrt[3]{28 - 1} \\f(14) = \sqrt[3]{27} \\f(14) = 3\)

\(f(x) = \sqrt[3]{2x - 1} \\f(-62) = \sqrt[3]{2(-62) - 1} \\f(-62) = \sqrt[3]{-124 - 1} \\f(-62) = \sqrt[3]{-125} \\f(-62) = -5\)

\(f(x) = \sqrt[3]{2x - 1} \\f(20) = \sqrt[3]{2(20) - 1} \\f(20) = \sqrt[3]{40 - 1} \\f(20) = \sqrt[3]{39}\)

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