\(\frac{2}{3} x + \frac{1}{6} = -\frac{3}{4} x + 1\)
First, simplify \(\frac{2}{3} x\) to \(\frac{2x}{3}\) / Your problem should look like: \(\frac{2x}{3} + \frac{1}{6} = -\frac{3}{4} x + 1\)
Second, simplify \(\frac{3}{4} x\) to \(\frac{3x}{4}\) / Your problem should look like: \(\frac{2x}{3} + \frac{1}{6} = -\frac{3x}{4} + 1\)
Third, multiply both sides by 12 (the LCM of 3 and 4) / Your problem should look like: \(8x + 2 = -9x + 12\)
Fourth, subtract 2 from both sides. / Your problem should look like: \(8x = -9x + 12 - 2\)
Fifth, simplify -9x + 12 - 2 to -9x + 10. / Your problem should look like: \(8x = -9x + 10\)
Sixth, add 9x to both sides. / Your problem should look like: \(8x + 9x = 10\)
Seventh, add 8x + 9x to get 17x. / Your problem should look like: \(17x = 10\)
Eighth, divide both sides by 17. / Your problem should look like: \(x = \frac{10}{17}\)
Answer as fraction: x = \(\frac{10}{17}\)
Answer as decimal: x = 0.5882
