Answered

When Carla looked out at the school parking lot, she noticed that for every 2 minivans , there were 5 other types of vehicles. If there are 161 vehicles in the parking lot, how many of them are not minivans?

Verified Answer :

TSO

\(2:5\\2x:5x\\2x+5x=7x\\\\7x = 161\\x=23\\\\5\times 23= \boxed {115} \leftarrow answer\)

calculista

Let

x--------> number of minivans at the school parking

y-------> number of other types of vehicles at the school parking

we know that

\(\frac{x}{y} =\frac{2}{5} \\\\ 5x=2y\)

\(y= 2.5x\) -----> equation \(1\)

\(x+y=161\) ------> equation \(2\)

Substitute equation \(1\) in equation \(2\)

\(x+(2.5x)=161\\\\ 3.5x=161\\\\ x=\frac{161}{3.5}\\\\x= 46\)

\(y=2.5*46\\ y=115\)

therefore

The number of minivans at the school parking is equal to \(46\)

The number of other types of vehicles at the school parking is equal to \(115\)

the answer is

The number of vehicles that are not minivans is \(115\)

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