NaiNai27
Answered

Look at points C and D on the graph:


What is the distance (in units) between points C and D? Round your answer to the nearest hundredth.



3.46 units

8.49 units

12.00 units

72.00 units

Look at points C and D on the graph: What is the distance (in units) between points C and D? Round your answer to the nearest hundredth. 3.46 units 8.49 units 1 class=

Verified Answer :

TSO

\(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\\sqrt{(0-6)^2+(2-(-4))^2}\\\\\sqrt{(-6)^2+6^2}\\\\\sqrt{36+36}\\\\\sqrt{72}\\\\\boxed{8.49}\)

JeanaShupp

Answer: 8.9 units


Step-by-step explanation:

From the given graph we can see the coordinates of C=(0,2)

The coordinates of D=(6,-4)

By using distance formula, we will find the distance between points C and D as:

CD=\(\sqrt{(x_2-x_1)^2+(y_2-y_1)2}\)

\(=\sqrt{(6-0)^2+(-4-2)^2}\\=\sqrt{6^2+(-6)^2}\\=\sqrt{36+36}\\=\sqrt{72}=6\sqrt{2}\\=6\times1.4142=8.4852\approx8.9\text{ units}\)