For the mineral torbernite, Cu(UO2)2(PO4)2⋅8H2O, determine the ratio, by number, of H atoms to O atoms
H:O = 4:5;
(UO₂)₂ = 4 O atoms;
(PO₄)₂ = 8 O atoms:
8H₂O = 16 H atoms + 8 O atoms;
Total = 16 H atoms + 20 O atoms;
H:O = 16:20 = 4:5
Answer:
The ratio by number of H atoms to O atoms is: 4:5
Explanation:
The mineral torbernite, : \(Cu(UO_2)_2(PO_4)2⋅8H_2O\)
Number of oxygen atoms in the mineral :
=\(2\times 2+4\times 2+8\times 1=20\)
Number of hydrogen atoms in the mineral :
=\(8\times 2=16\)
The ratio by number of H atoms to O atoms is:
\(\frac{16}{20}=\frac{4}{5}=4:5\)