There are 48 students in a school play. The ratio of boys to girls is 5:7. How many boys are in the school play? Explain how you found your answer
boys: x
gilrs: y
From the text of the task:
\(\left \{ {{\frac{x}{y}=\frac{5}{7}} \atop {x+y=48 \rightarrow x=48-y}} \right.\)
Replacing x:
\(\frac{48-y}{y}=\frac{5}{7}\\
\\
7(48-y)=5y\\
\\
336-7y=5y\\
\\
12y=336\\
\\
y=\frac{336}{12}=28\)
So there are 28 girs and 20 boys
Did you say that the ratio of boys to girls is 5 to 7 ?
Well, then we know that 5 'groups' in the cast are boys, and 7 'groups' are girls.
So all together, there are 12 'groups' of students in the play, although we don't know
how many a 'group' is.
But wait a second. You said there are 48 all together. So each 'group' must be
48/12 = 4 students.
5 'groups' of boys = 20 boys
7 'groups' of girls = 28 girls
Check:
-- The ratio of 20 to 28 is 5 to 7 . OK
-- 20 + 28 = 48 all together. OK
It all checks out.
yay