"Andrew has six fewer coins than Casey."
A=C-6
"Bob has four more than twice as many coins as Andrew."
B=2A+4
"Altogether, they have 466 coins."
A+B+C=466
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How many coins does Bob have?
B=2A+4
Therefore:
B=2(C-6)+4
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A+B+C=466,
Therefore:
(C-6)+(2(C-6)+4)+C=466
C-6+(2C-12+4)+C=466
C-6+(2C-8)+C=466
C-6+2C-8+C=466
4C-14=466
4C=480
C=120
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If C=120,
B=2(120-6)+4
B=2 x 114 + 4
B= 228 + 4
B=232
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A=120-6
A=114
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Answers (including Bob's):
Andrew has 114 coins. Casey has 120 coins. Bob has 232 coins.
114 + 120 + 232 = 466