??????????????????????????
??????????????????????????
\(\frac{4}{6}\) + \(\frac{2}{3}\)
First, simplify \(\frac{4}{6}\) to \(\frac{2}{3}\) / Your problem should look like: \(\frac{2}{3}\) + \(\frac{2}{3}\)
Second, join the denominators. / Your problem should look like: \(\frac{2+2}{3}\)
Third, simplify. / Your problem should look like: \(\frac{4}{3}\)
Fourth, convert to mixed fraction. / Your problem should look like: \(1\frac{1}{3}\)
Mixed number form: \(1\frac{1}{3}\)
Exact form: \(\frac{4}{3}\)
\(\frac{4}{6} + \frac{2}{3}\) = ?
You need to find a common denominator to add them which is 6
6×1=6 and 3×2=6
What you do on the denominator, you must do in the numerator
\(\frac{4}{6} + \frac{4}{5}\) = \(\frac{8}{6}\)
To reduce, find a common factor which in this case is 2
8÷2=4 and 6÷2=3 ⇒ \(\frac{4}{3}\)
To change to a mix fraction, divide the numerator by the denominator
\(\frac{4}{3}\) ⇒ \(1 \frac{1}{3}\)
Answer: \(\frac{4}{3}\) as an improper fraction or \(1 \frac{1}{3}\) as a mixed fraction