What's is the smallest power of 10 that would exceed 999,999,999,991?

10 to the power of any number HAS to only have 1 and zeroes in it.. A number that starts with 1, ends in zeros and is greater than 999,999,999,991 is 1,000,000,000,000

1,000,000,000,000 = \(10^{12}\) <-answer

(note: it has 12 zeroes)

Answer Link

pinquancaro pinquancaro · Answer 2 · 2019-09-10T01:33:04-04:00

Answer:

The required smallest power of 10 that would exceed 999,999,999,991 is 12.

Step-by-step explanation:

Given : Number 999,999,999,991.

To find : What's is the smallest power of 10 that would exceed number ?

Solution :

Let the required power be 'x'.

According to question,

\(10^x=999,999,999,991\)

Taking log both side,

\(\log (10^x)=\log(999,999,999,991)\)

Apply logarithmic property, \(\log a^x=x\log a\)

\(x\log (10)=\log(999,999,999,991)\)

\(x=\log(999,999,999,991)\)

Using calculator,

\(x=12\)

Therefore, The required smallest power of 10 that would exceed 999,999,999,991 is 12.