Verified Answer :

D3xt3R

We know that

\(1~mol\) have \(6.02\times10^{23}~molecules\)

therefore

\(0.589~mol\) have \(0.589*6.02\times10^{23}~molecules\approx3.55\times10^{23}~molecules\)

3.55 x 10^23 molecules are found in 0.589 of N2.

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