Verified Answer :

\(ax^2+bx+c=0\\\\4x^2=13x-3\\\\4x^2-13x+3=0\\\\a=4;\ b=-13;\ c=3\)

Answer:

a = 4

b = -13

c = 3

Step-by-step explanation:

We have been given the equation

\(4x^2=13x-3\)

Subtract \(4x^2\) to both sides of the equation

\(0=-4x^2+13x-3\)

Multiply both sides of the equation by -1

\(4x^2-13x+3=0\)

The general equation of a quadratic equation is \(ax^2+bx+c=0\)

Comparing this equation with above equation \(4x^2-13x+3=0\)

a = 4

b = -13

c = 3