Answer: There are \(\dfrac{4}{3}\) numbers of \(\dfrac{3}{4}\) in 1.
Step-by-step explanation: We are given to find the number of \(\drac{3}{4}\) in 1.
Let n be the number of \(\drac{3}{4}\) that are present in 1.
So, we must have
\(n\times\dfrac{3}{4}=1\\\\\\\Rightarrow n=\dfrac{1}{\frac{3}{4}}\\\\\\\Rightarrow n=1\times\dfrac{4}{3}\\\\\\\Rightarrow n=\dfrac{4}{3}.\)
Thus, there are \(\dfrac{4}{3}\) numbers of \(\dfrac{3}{4}\) in 1.