The solution of the equation for b is \(b = 2a - 5\) (b = 2a - 5)
To solve for b, that means we should make b the subject of the given equation.
From the given equation 10a-5b=25,
\(10a-5b=25\)
- First, Add 5b to both sides of the equation
\(10a-5b+5b=25+5b\)
We get
\(10a=25+5b\)
- Then, subtract 25 from both sides of the equation
\(10a-25=25-25+5b\)
We get
\(10a-25=5b\)
That is,
\(5b= 10a-25\)
- Now, divide both sides of the equation by 5
\(\frac{5b}{5} = \frac{10a-25}{5}\)
\(b= \frac{10a}{5}-\frac{25}{5}\)
\(b = 2a - 5\)
Hence, the solution of the equation for b is \(b = 2a - 5\) (b = 2a - 5)
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