Literal equations 2x-3y=8 solve for y
2x-3y = 8Add 3y on both sides2x = 8 + 3ySubtract 8 on both sides3y = 2x - 8Divide 3 on both sides\(y= \frac{2}{3}x- \frac{8}{3}\)
2x - 3y = 8- 3y = 8 - 2xy = ( 8 - 2x ) / -3 or2x - 3y = 8 2x = 8 + 3y2x - 8 = 3y(2x - 8) / 3 = y
