The sample space is orange, purple, and white. If P(Orange )=2/5 and P(purple) = 3/10 what is P=(white)
White would be 3/10. Since orange is 2/5, it can also be written as 4/10 since 4/10 simplified would be 2/5. Also since you know purple is 3/10, so you must add what you know to get what you don't know. Orange 4/10 plus purple 3/10 would be 7/10. You would then subtract what the whole thing is worth which is 10/10. 10/10 minus 7/10 would be 3/10 which is the remainder of what is left which is white.
Answer:
\(\frac{3}{10}\)
Step-by-step explanation:
Probability refers to chance of occurrence of an event .
Formula of probability :
Probability = No. of favourable outcomes / Total no. of outcomes
Let \(E_1\,,\,E_2\,,\,E_3\,,...\) be the events and S denotes the sample space .
Properties of Probability :
1 . \(\sum_{i=1}^{n}P(E_i)=1\)
2. \(0\leq P(E_i)\leq 1\)
Given :
P(Orange) = 2/5
P(purple) = 3/10
We know that P(Orange ) + P(purple) + P(white) = 1
So,
\(\frac{2}{5}+\frac{3}{10} +\) P(white) = 1
On transposing 2/5 and 3/10 on RHS , we get
P(white) = \(1-\frac{2}{5}-\frac{3}{10}=\frac{10-4-3}{10}=\frac{3}{10}\)