Point slope form of a line:
\(y-y_1=m(x-x_1)\) where \(m\) is your slope and \((x_1,\ y_1)\) is a point on your line.
For a line with a slope of 3/5 that passes through (10, -2)...
\(m=\frac35,\ x_1=10,\ y_1=-2\)
Let's plug these values into our formula.
\(y-(-2)=\frac35(x-10)\)
Subtracting by a negative is the same thing as adding (the double negatives cancel), so let's simplify that.
\(\boxed{y+2=\frac35(x-10)}\)
There's our equation in point-slope form. (keep in mind that you're not going to want to distribute that 3/5 or subtract the 2 or anything. You want to keep it similar to the formula.
