Answer:
-9 and -8
Step-by-step explanation:
We are given that
Product of two consecutive integers is 9 less than the square of the smaller number .
We have to find two consecutive integers
Let x and x+1 are two consecutive integers
According to question
\(x(x+)=x^2-9\)
Because x is smaller than x+1
\(x^2+x=x^2-9\)
\(x^2+x-x^2=-9\)
\(x=-9\)
Substitute the value of x then we get
\(x+1=-9+1=-8\)
Hence, the two consecutive integers are -9 and -8.
