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CarringtonKay CarringtonKay
  • 08-09-2015
  • Mathematics
Answered

X^2-6x+4=0

Please explain how to do quadratic formula with this problem.

Verified Answer :

Panoyin
Panoyin Panoyin
  • 08-09-2015

\(x^{2} - 6x + 4 = 0\)
\(\frac{-(-6) \± \sqrt{-(-6)^{2} - 4(1)(4)}}{2(1)}\)
\(\frac{6 \± \sqrt{36 - 16}}{2}\)
\(\frac{6 \± \sqrt{20}}{2}\)
\(\frac{6 \± 2\sqrt{5}}{2}\)
\(3 \± \sqrt{5}\)
\(3 + \sqrt{5}\)    \(or\)    \(3 - \sqrt{5}\)

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