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CharlynBlinks178 CharlynBlinks178
  • 20-05-2014
  • Mathematics
Answered

Proving Trigonometric Identities sec^2x + csc^2x= (sec^2 x)(csc^2 x)

Verified Answer :

Anonymous Anonymous
  • 20-05-2014

\(sec^2x+csc^2x=(sec^2x)(csc^2x)\\\\L=\frac{1}{cos^2x}+\frac{1}{sin^2x}=\frac{sin^2x}{cos^2xsin^2x}+\frac{cos^2x}{cos^2xsin^2x}=\frac{sin^2x+cos^2x}{cos^2xsin^2x}=\frac{1}{cos^2xsin^2x}\\\\=\frac{1}{cos^2x}\cdot\frac{1}{sin^2x}=sec^2x\cdot csc^2x=R\)

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