Verified Answer :

\(\sqrt{48n^9}=\sqrt{16n^8\cdot3n}=\sqrt{16n^8}\cdot\sqrt{3n}=4n^4\sqrt{3n}\)

Answer:

\(4n^4\sqrt{3n}\)

Step-by-step explanation:

Use the exponent rules:

\(\sqrt[n]{x^a} = x^{\frac{a}{n}}\)

\(\sqrt[n]{a^n} =a\)

To find the simplified form of :

\(\sqrt{48n^9}\)

We can write 48 and \(n^9\) as:

\(48 = 4 \cdot 4 \cdot 3 = 4^2 \cdot 3\)

\(n^9 = (n^4)^2 \cdot n\)

then;

\(\sqrt{4^2 \cdot 3 \cdot (n^4)^2 \cdot n}\)

Apply the exponent rule:

⇒\(4 \cdot n^4 \cdot \sqrt{3n}\)

⇒\(4n^4\sqrt{3n}\)

Therefore, the simplified form of square root 48n^9 is, \(4n^4\sqrt{3n}\)