how do you factor 3m^2 + 14m + 8 ?
3*8 = 24what adds to give us 14 which also multiplies to give us 24? 12 and 2(3m^2 + 12m) + (2m+8)factor out the 3m and the 23m(m+4)+2(m+4)(3m+2)(m+4) is your answer
\(3m^2 + 14m + 8\\ 3m^2 + 12m + 2m + 8\\3m(m+4) + 2(m+4)\\\\(m+4)(3m+2)\)
