Solve for x. What is 1/5[10-5(x-2)]=1/10(x+1)
\(\dfrac{1}{5}(10-5(x-2))=\dfrac{1}{10}(x+1)\\ 2(10-5x+10)=x+1\\ 2(-5x+20)=x+1\\ -10x+40=x+1\\ 11x=39\\ x=\dfrac{39}{11}\)