AC=3x+3,AB=-1+2x and BC=11 find x
∠AC = (3x + 3)°∠AB = (2x - 1)°∠BC = 11° ∠AC + ∠AB + ∠BC = 360° (3x + 3)° + (2x - 1)° + 11° = 360° 3x + 2x + 3 - 1 + 11 = 360 5x + 2 + 11 = 360 5x + 13 = 360 - 13 - 13 5x = 347 5 5 x = 69.4