Verified Answer :

Leader

There is one way that you can do it that involves multiplication, division, addition, and subtraction, and that uses all the numbers only once.

\(9 \div 3\times (7+1)\)

Solving it using PEMDAS, you get:

\(9\div3 \times 8\\\\3 \times 8\\\\24\)

So your answer is \(9 \div 3\times (7+1)\)

TSO

There are two answers to this.

\(\frac{9!}{7!} \times \frac{1}{3}= \frac{9\times 8 \times 7!}{7!} \times\frac{1}{3} = 9 \times 8 \times\frac{1}{3} = 3\times 8 = 24\)

But if you can only use addition, subtraction, multiplication, and division, you can also do:

\(\frac{9}{3} \times (7+1) = \frac{9}{3} \times 8 = 3 \times 8 = 24\)

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