\(\frac{-2(7-10)^{2} }{-3} +1\) equals 7.
First, simplify 7 - 10 to -3. Your problem should look like: -2 × \(\frac{(-3)^2}{-3} + 1\).
Second, since the power of 2 is even, the result will be positive. Your problem should look like: -2 × \(\frac{3^2}{-3} + 1\).
Third, simplify \(3^{2}\) to get 9. Your problem should look like: -2 × \(\frac{9}{-3} + 1\).
Fourth, simplify -2 × \(\frac{9}{-3}\) to 2 × \(\frac{9}{3}\). Your problem should look like: 2 × \(\frac{9}{3}\) + 1.
Fifth, simplify 2 × \(\frac{9}{3}\) to \(\frac{18}{3}\). Your problem should look like: \(\frac{18}{3} + 1\).
Sixth, simplify \(\frac{18}{3}\) to 6. Your problem should look like: 6 + 1.
Seventh, add 6 + 1. Your problem should look like: 7, which is your answer.
