Verified Answer :

iGreen

Plug -5 into both of them and divide:

\(\sf\dfrac{2x-20}{x-1}\)

\(\sf\dfrac{2(-5)-20}{-5-1}\)

Simplify:

\(\sf\dfrac{-10-20}{-6}\)

\(\sf\dfrac{-30}{-6}\)

\(\boxed{\sf 5}\)

Answer:

Option b is correct.

\((\frac{f}{g})(-5)\) = 5

Step-by-step explanation:

Given the functions:

\(f(x)=2x-20\)

\(g(x)=x-1\)

Solve: \((\frac{f}{g})(-5)\)

\((\frac{f}{g})(x) = \frac{f(x)}{g(x)}\)

Substitute the given function we have;

\((\frac{f}{g})(x) = \frac{2x-20}{x-1}\)

Put x = -5 we have;

\((\frac{f}{g})(-5) = \frac{2(-5)-20}{-5-1} =\frac{-10-20}{-6}=\frac{-30}{-6} = 5\)

therefore, the value of \((\frac{f}{g})(-5)\) is 5.



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