Answer:
Option b. 0.496
Step-by-step explanation:
we know that
\(f(x)=0.01(2^{x})\)
The average rate of change is equal to
\(\frac{f(b)-f(a)}{b-a}\)
where
\(a=3\)
\(b=8\)
\(f(a)=f(3)=0.01(2^{3})=0.08\)
\(f(b)=f(8)=0.01(2^{8})=2.56\)
Substitute
\(\frac{2.56-0.08}{8-3}\)
\(\frac{2.48}{5}\)
\(0.496\)
