For a school drama performance, student tickets cost $5 each and adult tickets cost $10 each. The sellers collected $3,570 from 512 tickets sold. If c is the number of student tickets sold, which equation can be used to find the amount of tickets sold of each type?
Answer:
The system of equations is equal to
\(a+c=512\)
\(5c+10a=3,570\)
The number of adult tickets sold is \(a=202\ tickets\)
The number of student tickets sold is \(c=310\ tickets\)
Step-by-step explanation:
Let
c------> the number of student tickets sold
a-----> the number of adult tickets sold
we know that
\(a+c=512\) -----> equation A
\(5c+10a=3,570\) -----> equation B
Using a graphing tool
The solution of the system of equations is the intersection point both graphs
see the attached figure
The intersection point is \((202,310)\)
therefore
the solution is
the number of adult tickets sold is \(a=202\ tickets\)
the number of student tickets sold is \(c=310\ tickets\)