Verified Answer :

TSO

Circumference = \(2 \pi r\)
6.28 = \(2 \pi r\)
r = 1

Area = \(\pi r^2\)
Area = \(\pi (1)\)
Area = 3.14

Hope that helps :)

Leader

Area of a circle = \(\pi r^{2}\)
Circumference of a circle = \(2 \pi r\) or \(\pi d\)

Circumference = \(\pi d\) = 6.28
d = 2
r = 1

Area = \(\pi (1)^{2}\) = 3.14

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