Verified Answer :

Hippalectryon

The reaction is \(3Cu+2Al^{3+}\rightarrow3Cu^{2+}+2Al\)

The semi equations are hence the following : \(Cu-=Cu^{2+}+2e^-, Al^{3+}+3e^-=Al\)

The substance being reduced is the one that gets the electrons.

Hence here it's Al

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