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Given the balanced equation representing a reaction:

4Al(s) + O2(g) --> 2Al2O3(s)

How many moles of Al(s) react completely with 4.50 moles of O2(g)to produce 3.00 moles of Al2O3(s)?

(1) 1.50 mol (2) 2.00 mol

(3) 6.00 mol (4) 4.00 mol

Verified Answer :

olemakpadu

4Al(s) + 3O2(g) --> 2Al2O3(s)    This is the balanced.
From the equation:

 4 moles of Al required 3 moles of O2 to produce 2 moles of Al2O3
 
3 moles of O2 reacted with 4 moles of Al to produce 2 moles of Al2O3
1 mole of O2 reacted with 4/3 moles of Al to produce 2/3 moles of Al2O3  (Divide by 3)
4.5 moles of O2 reacted with (4/3 4.5) moles of Al to produce (2/34.5) moles of Al2O3

4.5 moles of O2 reacted with 6moles of Al to produce  3moles of Al2O3

(3) is the answer.  6 mol of Al.

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