Verified Answer :

\(\boxed{b}\ and\ \boxed{d}\\\\b.\ \frac{1}{x^{-1}}=\left(\frac{1}{x}\right)^{-1}=x\\\\d.\ x^{\frac{1}{3}}\cdot x^{\frac{1}{3}}\cdot x^{\frac{1}{3}}=x^{\frac{1}{3}+\frac{1}{3}+\frac{1}{3}}=x^{\frac{3}{3}}=x^1=x\)

Answer:

b and d

Step-by-step explanation:

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