Melita571
Answered

Which shows one way to determine the factors of x^3 – 12x^2 – 2x + 24 by grouping?

Ax(x^2 – 12) + 2(x2 – 12)
Bx(x^2 – 12) – 2(x2 – 12)
Cx^2(x – 12) + 2(x – 12)
Dx^2(x – 12) – 2(x – 12)

Verified Answer :

\(x^3-12x^2-2x+24=x^2\cdot x-x^2\cdot12-2\cdot x-2\cdot(-12)\\\\=\underline{x^2(x-12)-2(x-12)}=(x-12)(x^2-2)\\\\Answer:\boxed{d}\)

demchykandriy

The answer is D on e2020.

x^2(x-12)-2(x-12)

Have a great day

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