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Sylvanite is a mineral that contains 28.0% \% gold by mass. How much sylvanite would you need to dig up to obtain 34.0g g of gold?

Verified Answer :

taskmasters

Since it is said the 1g of
mineral contains 28% of gold which is equivalent to .28g of gold.

Thus, .28 gram of Gold = 100 grams
of Minerals

=> 1g of Gold = 100/28 grams
of Minerals

=> 34grams of gold = 100/28 *
34 g of Minerals

=> 34 grams of gold = 952 grams of Minerals


Therefore, it needs 952 grams of
Sylvanite minerals in order to have 34 grams of Gold.





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