A laboratory requires 2.0 L of a 1.5 M solution of hydrochloric acid (HCl), but the only available HCl is a 12.0 M stock solution. How could you prepare the solution needed for the lab experiment? show all work to find your answer
The amount of the solute is constant during dilution. So the mole number of HCl is 2*1.5=3 mole. The volume of HCl stock is 3/12=0.25 L. So using 0.25 L stock solution and dilute to 2.0 L.
Answer: The volume of stock HCl solution required to make laboratory solution will be 0.25L
Explanation:
To calculate the volume of stock solution required to make the laboratory solution, we use the equation:
\(M_1V_1=M_2V_2\)
where,
\(M_1\text{ and }V_1\) are the molarity and volume of stock solution.
\(M_2\text{ and }V_2\) are the molarity and volume of laboratory solution.
We are given:
\(M_1=12M\\V_1=?L\\M_2=1.5M\\V_2=2L\)
Putting values in above equation, we get:
\(12\times V_1=1.5\times 2\\\\V_1=0.25L\)
Hence, the volume of stock HCl solution required to make laboratory solution will be 0.25L