what is x cubed minus 8
Since \(x^3-8\) is a sum of cubes, (-8 is -2 cubed) it can be factored like so:\(a^3+b^3=(a+b)(a^2-ab+b^2)\)\(a^3=x^3\implies a=x\)\(b^3=-8\implies b=-2\)\(x^3-8=(x+(-2))(x^2-x(-2)+(-2)^2)=\boxed{(x-2)(x^2+2x+4)}\)
