5p+9c=p solve for c I am confused on how to do it
\(5p+9c=p\ \ \ \ |subtract\ 5p\ from\ both\ sides\\\\9c=-4p\ \ \ \ |divide\ both\ sides\ by\ 9\\\\\boxed{c=\frac{-4p}{9}\to \huge\boxed{c=-\frac{4}{9}p}}\)