Answer: 5.08 moles
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number \(6.023\times 10^{23}\) of particles.
To calculate the number of moles, we use the equation:
\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\)
given mass of Cesium (Cs) = 675 g
Molar mass of Cesium (Cs) = 132.90 g/mol
Putting in the values we get:
\(\text{Number of moles}=\frac{675g}{132.90g/mol}=5.08moles\)
Thus there are 5.08 moles of cesium in 675 g of cesium.
