Factor completely: 3x2 – 24x + 36 A. (3x – 2)(x – 18) B. 3(x – 2)(x – 6) C. (x – 2)(x – 6) D. 2(x – 3)(x – 12)
\(3x^2- 24x + 36=\\ 3(x^2-8x+12)=\\ 3(x^2-6x-2x+12)=\\ 3(x(x-6)-2(x-6))=\\ 3(x-2)(x-6)\)
\(3x^{2}-24x+36=3(x^{2}-8x+12)=3(x^{2}-2x-6x+12)= \\ \\ =3[x(x-2)-6(x-2)]=3(x-6)(x-2)\)
\\\ Ben