Which equation could be used to solve this problem? The sum of two consecutive odd integers is 100. Find the integers. A.2n + 3 = 100 B.2n + 1 = 100 C.n + 4 = 100 D.2n + 2 = 100
an even integer is represented as 2n where n is an integer. an odd integer is represented as 2n+1
all even numbers are 2 away from the next even number
all odd numers are 2 away from the next odd number so
the sum of 2 consecutive odd intergesrs s 100
consecutive odd=(2n+1)+(2n+1+2) and so on
so consecutive odd =100 so
2n+1+2n+1+2=100
4n+4=100
the closest equation is
the equation is 4n+4
odd integers - 2n+1
consecutive odd integers - 2n+1 + 2
equation 2x+1+2x+1+2=4n+4
\(4n+4=100\\
4n=96\\
n=24\\\\
2n+1=49\\
2n+3=51\\
49+51=100\)
the integers are 49 and 51
Maja