Answer:
The correct option is 4.
Step-by-step explanation:
The given equation is
\(x^2-2x-3=0\)
If an expression is \(x^2+bx\), then to make it perfect sqaure add \((\frac{b}{2})^2\).
\((x^2-2x)-3=0\)
Here b=-2,to make the perfect square we need to add \((\frac{-2}{2})^2\),i.e, 1.
\((x^2-2x+1)-1-3=0\)
\((x-1)^2-4=0\) \([\because (a-b)^2=a^2-2ab+b^2]\)
Add 4 on both the sides.
\((x-1)^2-4+4=0+4\)
\((x-1)^2=4\)
Therefore the correct option is 4.
