Verified Answer :

Benjamin16

\(g^{2}-28g+196=g^{2}-14g-14g+196=g(g-14)-14(g-14)= \\ \\ (g-14)(g-14)=(g-14)^{2}\)

P.S :>

\((a-b)^{2}=a^{2}-2ab+b^{2}\)

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TSO

We can use this formula:

\(\sf{x^2-2xy+y^2 =(x-y)(x-y)=(x-y)^{2}}\)

\(g^2 - 28g + 196 \to (g)^2 - 2(14)(g) + (14)^2\)

that means:

\(x = g, y = 14\)

So plugging that into the formula, you get:

\(g^2 - 28g + 196= (g-14)(g-14)= (g-14)^2\)

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