Verified Answer :

We start with the given expression and then simplify:

\(\sqrt{128}\)

\(\sqrt{64*2}\)

\(8 \sqrt{2}\)

Since 2 has no perfect square factors, this radical is now as simplified as possible.

apologiabiology

√128
facotr and find pairs for squares that can go out of the radical (√)
128=2 times 2 times 2 times 2 times 2 times 2 times 2
group the pairs
(2 times 2)(2 times 2)(2 times 2) times 2
write one of each pair outside
2 times 2 times 2√2
8√2 is the naswer

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