what is 143/15 simplified
\(\sf \frac{143}{15}=?\)
\(\sf{ 15 \times 9 = 135}\)
\(\sf{143- 135 = 8}\)
\(\sf{ \frac{143}{15} = \frac{135+8}{15} = \frac{135}{135} + \frac{8}{15}\)
\(\sf{ \frac{143}{15} =\boxed{\huge{ 9 \frac{8}{15} }}}\)
Since the GCF is 1, all we have to do is divide! :D
\(\pmb{143 \div 15 } \\ \\ = 9 \hbox remainder 8 } \\ \\ \boxed{\boxed{\huge{9 \frac{8}{15} }}}\)
The denominator remains the same while the numerator is what you get as a remainder :D