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missyconnors missyconnors
  • 09-08-2015
  • Mathematics
Answered



Find the domain of f(x)=square root x^2−36.



Select one:

Ax≥6 or x≤−6
Bx≥36
Call real numbers
Dx≥6

Verified Answer :

Benjamin16
Benjamin16 Benjamin16
  • 09-08-2015

\(f(x)= \sqrt{x^{2}-36} \\ \\ D: x^{2}-36 \geq 0 \\ \\ (x-6)(x+6) \geq 0 \\ \\ x+6=0 \ \vee \ x-6=0 \\ \\ x=-6 \ \vee \ x=6 \\ \\ x\in (-\infty,-6 ) \ \cup \ (6,+\infty)\)

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