Mason used 1/6 of a gram of honey to make 1/12 of a pan of pudding. How many grams are needed to make a full pan of pudding?
so with 1/6 gram of honey you can make 1/12 pan of pudding
that means with 6/6 or 1 gram of honey you can make 6/12 pan of pudding
then 2 gram of honey is needed to make 12/12 or 1 full pan of pudding
Answer:
2 grams
Step-by-step explanation:
Given,
Quantity of honey required for \(\frac{1}{12}\) part of pudding = \(\frac{1}{6}\) grams,
Since, total part of pudding = 1,
The number of \(\frac{1}{12}\) parts in the pudding = 12,
So, the number of gram of honey needed for 1 full part of pudding = number of \(\frac{1}{12}\) parts × honey required for \(\frac{1}{12}\) part,
= 12 × \(\frac{1}{6}\)
= \(\frac{12}{6}\)
= 2