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Cameron877
Cameron877 Cameron877
  • 07-08-2015
  • Mathematics
Answered

What is the center of a circle given by the equation (x + 5) squared + (y - 8) squared equals one?

Verified Answer :

konrad509
konrad509 konrad509
  • 07-08-2015

\((x-h)^2+(y-k)^2=r^2\\ \text{center}=(h,k)\\\\ (x+5)^2+(y-8)^2=1\\ \text{center}=(-5,8)\)

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TSO
TSO TSO
  • 07-08-2015

\((x+5)^2 +(y-8)^2 = 1\)

\((x-h)^2 +(y-k)^2 = r^2\)

then the center of the circle is 

\((h,k)\)

So the center of the circle for your question would be:

(-5, 8)

Answer Link

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