A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is 1 over 9, and the probability of randomly pulling out a strawberry candy is 3 over 9, what is the probability of randomly pulling out a pineapple candy?

To find this add 3 and 1 together. This gives you 4. Then, you subtract 4 from 9. The answer is 5. Therefore, the probability to pull out a pineapple candy would be 5/9.

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virtuematane virtuematane · Answer 2 · 2019-06-14T05:31:22-04:00

Answer:

The probability of randomly pulling out a pineapple candy is:

\(\dfrac{5}{9}\)

Step-by-step explanation:

There are three flavors in a ice cream namely:

orange, strawberry, and pineapple.

We know that for any three events in a single experiment the sum of the probability of three events is equal to 1.

i.e. if A, B and C are three events and P denotes the probability of an event then:

P(A)+P(B)+P(C)=1

Here let A= flavor is orange

B= flavor is strawberry

and C= flavor is pineapple.

and we have:

\(P(A)=\dfrac{1}{9},\ P(B)=\dfrac{3}{9}\)

Hence, we have:

\(\dfrac{1}{9}+\dfrac{3}{9}+P(C)=1\\\\\\i.e.\\\\\\\dfrac{4}{9}+P(C)=1\\\\\\i.e.\\\\\\P(C)=1-\dfrac{4}{9}\\\\\\i.e.\\\\\\P(C)=\dfrac{9-4}{9}\\\\i.e.\\\\P(C)=\dfrac{5}{9}\)