\(216x^{12}-64=8(27x^{12} - 8) = 8[(3x^{4})^{3} - 2^{3}] = \\ \\ =8(3x^{4}-2)(9x^{8} +6x^{4} +4) = 2(3x^{4}-2)*4(9x^{8}+6x^{4}+4)= \\ \\ (6x^{4}-4)(36x^{8}+24x^{4}+16)\)
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a^3-b^3=(a-b)(a^2+ab+b^2)
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