Answered

There are 4 red balls, 6 white balls, and 3 blue balls in a bag. If one ball is drawn from the bag at random, what is the probability that it is not white?

A1/7
B5/6
C7/13
D1/13

Verified Answer :

First you want to add all the numbers up.  Then you have to subtract from the amount of white balls (which will give you seven).  Put 7 above the sum of all the balls and so the chances of getting a ball that is not white would be 7/13.

Benjamin16

\(P'(A) = \frac{6}{4+6+3}= \frac{6}{13} \\ \\ P(A) = 1-P'(A) \\ \\ P(A)=1- \frac{6}{13}= \frac{7}{13}\)

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